We have seen that the electrical power developed in the rotor is converted into mechanical power which is given by the following relation:
Mechanical power developed in the rotor 
The rotor copper losses ![]()
Rotor input = Mechanical power developed + rotor copper losses

From eq. (12.3) and (12.4), we get, 
∴ Rotor copper loss
Mechanical power developed
From eq. (12.4) and (12.5), we get, 
∴ Rotor copper loss = S × Rotor input
Note: All the values are the phase values.

Leave a Reply