{"id":1619,"date":"2024-07-25T20:11:58","date_gmt":"2024-07-25T20:11:58","guid":{"rendered":"https:\/\/workhouse.sweetdishy.com\/?p=1619"},"modified":"2024-07-25T20:11:58","modified_gmt":"2024-07-25T20:11:58","slug":"similarity-between-heat-and-work","status":"publish","type":"post","link":"https:\/\/workhouse.sweetdishy.com\/index.php\/2024\/07\/25\/similarity-between-heat-and-work\/","title":{"rendered":"Similarity Between Heat and Work"},"content":{"rendered":"\n<p id=\"para-101\">Heat and work are energy transfer mechanisms between a system and its surroundings. Some of the similarities between heat and work are as follows:<\/p>\n\n\n\n<ul class=\"wp-block-list\" id=\"ul-005\">\n<li>Heat and work are boundary phenomena.<\/li>\n\n\n\n<li>Systems possess energy, but not heat or work.<\/li>\n\n\n\n<li>Both are associated with a process, not a state.<\/li>\n\n\n\n<li>Both are path functions.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h4-013\">1.4.5&nbsp;&nbsp;Non-flow Processes<\/h4>\n\n\n\n<p id=\"para-102\">The various non-flow processes and their characteristics are shown in&nbsp;<a href=\"https:\/\/learning.oreilly.com\/library\/view\/basic-mechanical-engineering\/9789332524415\/xhtml\/chapter001.xhtml#img-010\">Figure 1.3.<\/a><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page10a.png\" alt=\"Figure 1.3\"\/><\/figure>\n\n\n\n<p id=\"para-103\"><strong>Figure 1.3<\/strong>&nbsp;Non-flow Processes<\/p>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h4-014\">Constant Volume Process<\/h4>\n\n\n\n<p id=\"para-104\">In this process, volume remains constant, i.e., \u0394<em>V<\/em>&nbsp;= 0. This is also known as isochoric process. From first law of thermodynamics:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page10b.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h4-015\">Constant Pressure Process<\/h4>\n\n\n\n<p id=\"para-105\">In this process, pressure remains constant, i.e., \u0394<em>p<\/em>&nbsp;= 0. This is also known as isobaric process.<\/p>\n\n\n\n<p id=\"para-106\">The work done from state 1 to state 2.<\/p>\n\n\n\n<p id=\"para-107\">&nbsp;<\/p>\n\n\n\n<p><em>W<\/em>&nbsp;=&nbsp;<em>pdV<\/em>&nbsp;=&nbsp;<em>p<\/em>(<em>V<\/em><sub>1<\/sub><em>&nbsp;\u2212&nbsp;V<\/em><sub>2<\/sub>)<\/p>\n\n\n\n<p id=\"para-108\">&nbsp;<\/p>\n\n\n\n<p id=\"para-109\">From first law of thermodynamics<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page10c.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h4-016\">Constant Temperature Process<\/h4>\n\n\n\n<p id=\"para-110\">In this process, temperature remains constant, i.e., \u0394<em>T<\/em>&nbsp;= 0. This is also known as isothermal process.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page10d.png\" alt=\"equation\"\/><\/figure>\n\n\n\n<p id=\"para-113\"><a><\/a>From first law of thermodynamics<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page11a.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h4-017\">Adiabatic Process<\/h4>\n\n\n\n<p id=\"para-114\">In this process, heat transfer is equal to zero.<\/p>\n\n\n\n<p id=\"para-115\">Work done during adiabatic process<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page11b.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-116\">From first law of thermodynamics<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page11c.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h4-018\">Polytropic Process<\/h4>\n\n\n\n<p id=\"para-117\">In this process, the law is governed by&nbsp;<em>PV<sup>n<\/sup><\/em>&nbsp;= constant.<\/p>\n\n\n\n<p id=\"para-118\">Work done during adiabatic process<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page11d.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-119\">From first law of thermodynamics<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page11e.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-120\">\u00a0The initial pressure and temperature of 1 mole of an ideal gas are 1 MPa and 380 K, respectively. It is heated at constant pressure till the temperature is doubled and then is allowed to\u00a0expand reversibly and adiabatically till the temperature is reduced to 380 K as shown in\u00a0Figure 1.4,\u00a0find the heat transferred and work interaction. If it is required to restore the system from final state to original state by a reversible isothermal path, determine the amount of work to be done on system.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page12b.png\" alt=\"Figure 1.4\"\/><\/figure>\n\n\n\n<p id=\"para-121\"><strong>Figure 1.4<\/strong>&nbsp;<em>P\u2013V<\/em>&nbsp;Diagram<\/p>\n\n\n\n<p id=\"para-122\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p id=\"para-123\"><em>P\u2013V<\/em>\u00a0diagram for the process is shown in\u00a0Figure 1.4.<\/p>\n\n\n\n<p id=\"para-124\">Let&nbsp;<em>P<\/em><sub>1<\/sub>&nbsp;= 1MPa,&nbsp;<em>T<\/em><sub>l<\/sub>&nbsp;= 380K,&nbsp;<em>T<\/em><sub>2<\/sub>&nbsp;= 2,&nbsp;<em>T<\/em><sub>l<\/sub>&nbsp;= 2 \u00d7 380 = 760K<\/p>\n\n\n\n<p id=\"para-125\">Since from 1 to 2 pressure is constant<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page12a.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-126\">Change in internal energy in the process 2 to 3,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page12c.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-127\">For the process 2 \u2212 3<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page12d.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-128\">here &nbsp;&nbsp;<em>Q<\/em><sub>2\u20133<\/sub>&nbsp;= 0,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page012_1.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-130\">For the reversible isothermal process<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page12e.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-131\"><strong>Example 1.3:<\/strong>&nbsp;A system undergoes the cyclic process abcde. The values of&nbsp;<em>Q, W<\/em>, and \u0394<em>u<\/em>&nbsp;for the individual process are as follows:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page12f.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-132\"><a><\/a><strong>Solution:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page013_1.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-139\"><strong>Example 1.4:<\/strong>&nbsp;There is a cylinder-piston system in which pressure is a function of volume as&nbsp;<em>P<\/em>&nbsp;=&nbsp;<em>x<\/em>&nbsp;+&nbsp;<em>yV<\/em>&nbsp;and internal energy is given by&nbsp;<em>u<\/em>&nbsp;= 36 + 3.16<em>PV<\/em>, where&nbsp;<em>u<\/em>&nbsp;is in kJ,&nbsp;<em>P<\/em>&nbsp;is in kN\/m<sup>2<\/sup>,&nbsp;<em>V<\/em>&nbsp;is in m<sup>3<\/sup>. If gas changes state from 150 kN\/m<sup>2<\/sup>&nbsp;and 0.02 m<sup>2<\/sup>&nbsp;to 350 kN\/m<sup>2<\/sup>&nbsp;and 0.04 m<sup>2<\/sup>, find the heat and work interaction.<\/p>\n\n\n\n<p id=\"para-140\"><strong>Solution:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page13.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-141\">On solving these two equations, we get&nbsp;<em>x<\/em>&nbsp;= \u221250 kN\/m<sup>2<\/sup>&nbsp;and&nbsp;<em>y<\/em>&nbsp;= 10,000 kN\/m<sup>2<\/sup><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page13a.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-142\"><strong>Example 1.5:<\/strong>&nbsp;Calculate the quantities of work if initial pressure and volume are 15 bar and 15 m<sup>3<\/sup>&nbsp;and final volume 25 m<sup>3<\/sup>. The process is non-flow reversible as (i)&nbsp;<em>P<\/em>&nbsp;= constant; (ii)&nbsp;<em>V<\/em>&nbsp;= constant; (iii)&nbsp;<em>PV<\/em>&nbsp;= constant; (iv)&nbsp;<em>PV<sup>n<\/sup><\/em>&nbsp;= constant, where&nbsp;<em>n<\/em>&nbsp;= 1.3; and (<em>v<\/em>)&nbsp;<em>PV<\/em><sup>&nbsp;\u03b3<\/sup>&nbsp;= constant, where&nbsp;<em>\u03b3<\/em>&nbsp;= 1.4.<\/p>\n\n\n\n<p id=\"para-143\"><strong>Solution:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\" id=\"ol-001\">\n<li>&nbsp;<img loading=\"lazy\" decoding=\"async\" alt=\"equation\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page13b.png\" width=\"344\" height=\"68\"><\/li>\n\n\n\n<li>&nbsp;&nbsp;<img loading=\"lazy\" decoding=\"async\" alt=\"equation\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page13c.png\" width=\"94\" height=\"68\"><\/li>\n\n\n\n<li>&nbsp;&nbsp;<img loading=\"lazy\" decoding=\"async\" alt=\"equation\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page13d.png\" width=\"313\" height=\"68\"><\/li>\n\n\n\n<li>&nbsp;<a><\/a>&nbsp;<img loading=\"lazy\" decoding=\"async\" alt=\"equation\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page14a.png\" width=\"402\" height=\"160\"><\/li>\n\n\n\n<li>&nbsp;&nbsp;<img loading=\"lazy\" decoding=\"async\" alt=\"equation\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page14b.png\" width=\"404\" height=\"160\"><\/li>\n<\/ol>\n\n\n\n<p id=\"para-144\"><strong>Example 1.6:<\/strong>&nbsp;A cylinder consists of a frictionless spring loaded piston as shown in&nbsp;<a href=\"https:\/\/learning.oreilly.com\/library\/view\/basic-mechanical-engineering\/9789332524415\/xhtml\/chapter001.xhtml#img-036\">Figure 1.5;&nbsp;<\/a>the pressure of gas at an instant is 5 bar. The spring force exerted on the piston is proportional to the volume of gas. Also, additional atmospheric pressure of 1 bar acts on spring side of piston as shown in&nbsp;<a href=\"https:\/\/learning.oreilly.com\/library\/view\/basic-mechanical-engineering\/9789332524415\/xhtml\/chapter001.xhtml#img-036\">Figure 1.5.<\/a>&nbsp;Calculate the work done by gas in expansion from 0.2 to 0.8 m<sup>3<\/sup>.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page14c.png\" alt=\"Figure 1.5\"\/><\/figure>\n\n\n\n<p id=\"para-145\"><strong>Figure 1.5<\/strong>&nbsp;Cylinder Piston Arrangement<\/p>\n\n\n\n<p id=\"para-146\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p id=\"para-147\">The pressure exerted on spring by the piston,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page14d.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-148\"><strong>Example 1.7:<\/strong>&nbsp;A cylinder fitted with a piston has an initial volume of 0.1 m<sup>3<\/sup>&nbsp;and contains nitrogen at 150 kPa, 25\u00b0C. The piston is moved compressing the nitrogen until the pressure becomes 1 MPa and temperature becomes 150\u00b0C. During the compression process heat is transferred from nitrogen and work done on nitrogen is 20 kJ. Determine the amount of this heat transfer. Assume&nbsp;<em>R<\/em>&nbsp;= 2,968 J\/kg K and&nbsp;<em>C<sub>v<\/sub><\/em>&nbsp;= 743 J\/kg.<\/p>\n\n\n\n<p id=\"para-149\"><a><\/a><strong>Solution:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page15a.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-150\"><strong>Example 1.8:<\/strong>\u00a0Figure 1.6\u00a0shows two reversible process a \u2212 b \u2212 c \u2212 a and a \u2212 d \u2212 c \u2212 a. Change in internal energy from c to a is 50 kJ and work done by the system during the process a \u2212 d is 30 kJ. Find<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page15b.png\" alt=\"Figure 1.6\"\/><\/figure>\n\n\n\n<p id=\"para-151\"><strong>Figure 1.6<\/strong>&nbsp;<em>P\u2013V<\/em>&nbsp;Diagram<\/p>\n\n\n\n<ul class=\"wp-block-list\" id=\"ul-006\">\n<li>Heat interaction during the process a \u2212 b \u2212 c.<\/li>\n\n\n\n<li>Heat interaction during the process a \u2212 d \u2212 c if work done during d \u2212 c is 10 kJ.<\/li>\n\n\n\n<li>Heat interaction during the process c \u2212 a if work done on the system during the process c \u2212 a is 20 kJ.<\/li>\n<\/ul>\n\n\n\n<p id=\"para-152\"><strong>Solution:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\" id=\"ol-002\">\n<li>&nbsp;&nbsp;<img loading=\"lazy\" decoding=\"async\" alt=\"equation\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page15c.png\" width=\"372\" height=\"86\"><\/li>\n\n\n\n<li>&nbsp;&nbsp;<img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page15d.png\" alt=\"equation\" width=\"350\"><\/li>\n\n\n\n<li>&nbsp;&nbsp;<img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page15e.png\" alt=\"equation\" width=\"350\"><\/li>\n<\/ol>\n\n\n\n<p id=\"para-153\"><strong>Example 1.9:<\/strong>&nbsp;A hydraulic brake is used to test an engine at speed of 1,200 rpm. The measured torque of the engine is 15,000 N m and the water flow rate is 0.8 m<sup>3<\/sup>\/s, its inlet temperature is 15\u00b0C. Calculate the water temperature at exit, assuming that the whole of the engine power is ultimately transformed into heat which is absorbed by the water flow.<\/p>\n\n\n\n<p id=\"para-154\"><strong>Solution:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page15f.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-155\"><strong><a><\/a>Example 1.10:<\/strong>&nbsp;In a cyclic process, amount of heat transfers are given as 15J, \u221227, \u22124 and 32 kJ. Calculate the net work done in the cyclic process.<\/p>\n\n\n\n<p id=\"para-156\"><strong>Solution:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page016_1.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-158\"><strong>Example 1.11:<\/strong>&nbsp;In a cyclic process, an engine engages in two work interactions: 18 kJ to the fluid and 48 kJ from the fluid, and two heat interactions out of three are given as: 80 kJ to the fluid and 44 kJ from the fluid. Find the magnitude and direction of the third heat transfer.<\/p>\n\n\n\n<p id=\"para-159\"><strong>Solution:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page016_3.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-162\"><strong>Example 1.12:<\/strong>&nbsp;During a certain period of analysis, a refrigerator consuming the energy at the rate of 1.5 kJ\/h loses internal energy of its system by 4,500 kJ. Calculate the heat transfer for the system for that period.<\/p>\n\n\n\n<p id=\"para-163\"><strong>Solution:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332524415\/files\/images\/page016_5.png\" alt=\"Equation\"\/><\/figure>\n\n\n\n<p id=\"para-166\"><strong>Example 1.13:<\/strong>&nbsp;Two kilograms of water having a constant specific heat 4.18 kJ\/kg K is stirred in a well-insulated jar results in rise of temperature by 18\u00b0C. Find the \u0394<em>u<\/em>&nbsp;and&nbsp;<em>W<\/em>&nbsp;of the process.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Heat and work are energy transfer mechanisms between a system and its surroundings. Some of the similarities between heat and work are as follows: 1.4.5&nbsp;&nbsp;Non-flow Processes The various non-flow processes and their characteristics are shown in&nbsp;Figure 1.3. Figure 1.3&nbsp;Non-flow Processes Constant Volume Process In this process, volume remains constant, i.e., \u0394V&nbsp;= 0. This is also [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":1607,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-1619","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-blog"],"jetpack_featured_media_url":"https:\/\/workhouse.sweetdishy.com\/wp-content\/uploads\/2024\/07\/thermometer.png","_links":{"self":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/1619","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/comments?post=1619"}],"version-history":[{"count":1,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/1619\/revisions"}],"predecessor-version":[{"id":1620,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/1619\/revisions\/1620"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media\/1607"}],"wp:attachment":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media?parent=1619"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/categories?post=1619"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/tags?post=1619"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}