{"id":2873,"date":"2024-08-25T20:01:49","date_gmt":"2024-08-25T20:01:49","guid":{"rendered":"https:\/\/workhouse.sweetdishy.com\/?p=2873"},"modified":"2024-08-25T20:01:50","modified_gmt":"2024-08-25T20:01:50","slug":"all-day-efficiency","status":"publish","type":"post","link":"https:\/\/workhouse.sweetdishy.com\/index.php\/2024\/08\/25\/all-day-efficiency\/","title":{"rendered":"ALL-DAY EFFICIENCY"},"content":{"rendered":"\n<p id=\"para-756\">The efficiency discussed so far is the ordinary or commercial efficiency which is given by the ratio of output power to input power, that is,<\/p>\n\n\n\n<p id=\"para-757\">Commercial efficiency,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page548_3.png\" alt=\"img\"\/><\/figure>\n\n\n\n<p id=\"para-758\">The load on certain transformers fluctuate throughout the day. The distribution transformers are energized for 24 h, but they deliver very light loads for major portion of the day. Thus, iron losses occur for whole day, but copper losses occur only when the transformer are loaded. Hence, the performance of such transformers cannot be judged by the commercial efficiency, but it can be judged by all-day efficiency also known as operational efficiency or energy efficiency which is computed on the basis of energy consumed during a period of 24 h.<\/p>\n\n\n\n<p id=\"para-759\">The all-day efficiency is defined as the ratio of output in kWh (or Wh) to the input in kWh (or Wh) of a transformer over 24 h.<\/p>\n\n\n\n<p id=\"para-760\">\u2234<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page548_4.png\" alt=\"img\"\/><\/figure>\n\n\n\n<p id=\"para-761\">To find this all-day efficiency, we have to know the load cycle on the transformer.<\/p>\n\n\n\n<p id=\"para-762\"><strong>Example 10.33<\/strong><\/p>\n\n\n\n<p id=\"para-763\">A 20 kVA transformer on domestic load, which can be taken as of unity power factor, has a full-load efficiency of 94.3%, the copper loss then being twice the iron loss. Calculate its all-day efficiency on the following daily cycle; no-load for 10 h, half load for 8 h, and full load for 6 h<em>.<\/em><\/p>\n\n\n\n<p id=\"para-764\"><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-765\">Full-load output = 20 \u00d7 1 = 20 kW<\/p>\n\n\n\n<p id=\"para-766\">Full-load input =&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page548_5.png\" alt=\"img\" width=\"323\" height=\"66\"><\/p>\n\n\n\n<p id=\"para-767\">Total losses,&nbsp;<em>P<\/em><sub>i<\/sub>&nbsp;+&nbsp;<em>P<\/em><sub>c&nbsp;<\/sub>= 20.986 \u2212 20 = 0\u00b7986 kW<\/p>\n\n\n\n<p id=\"para-768\">Now,&nbsp;<em>P<\/em><sub>c<\/sub>&nbsp;= 2<em>P<\/em><sub>i<\/sub>&nbsp;(given)&nbsp;<em>P<\/em><sub>i&nbsp;<\/sub>+ 2<em>P<\/em><sub>i&nbsp;<\/sub>= 0.986 kW<\/p>\n\n\n\n<p id=\"para-769\">Or lron losses,&nbsp;<em>P<\/em><sub>i&nbsp;<\/sub>= 0.3287 kW<\/p>\n\n\n\n<p id=\"para-770\">Full-load copper losses = 2 \u00d7 0.3287 = 0.6574 kW<\/p>\n\n\n\n<p id=\"para-771\">kWh output in 24 h =&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page547_2.png\" alt=\"img\" width=\"20\" height=\"60\">&nbsp;\u00d7 20 \u00d7 8 + 1 \u00d7 20 \u00d7 6 = 200 kWh<\/p>\n\n\n\n<p id=\"para-772\">Iron losses for 24 h = 0.3287 \u00d7 24 = 7.89 kWh<\/p>\n\n\n\n<p id=\"para-773\">Copper losses for 24 h = cu. losses for 8 h at&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page547_2.png\" alt=\"img\" width=\"20\" height=\"60\">&nbsp;full load + cu. losses for 6 h at full load<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page549_1.png\" alt=\"img\"\/><\/figure>\n\n\n\n<p id=\"para-774\">input in 24 h = kWh output in 24 h + iron and cu losses in kWh for 24 h<\/p>\n\n\n\n<p id=\"para-775\">&nbsp;<\/p>\n\n\n\n<p>= 200 + 7.89 + 5.259 = 213.149 kWh<\/p>\n\n\n\n<p id=\"para-776\">All day efficiency,&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page549_2.png\" alt=\"img\" width=\"574\" height=\"62\"><\/p>\n\n\n\n<p id=\"para-777\"><strong>Example 10.34<\/strong><\/p>\n\n\n\n<p id=\"para-778\">A 5 kVA single-phase transformer has a core loss of 50 W and full-load ohmic loss of 100 W. The daily variation of load on the transformer is as follows:<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td>7 am to 1 pm<\/td><td>3 kW at power factor 0.6 lagging.<\/td><\/tr><tr><td>1 pm to 6 pm<\/td><td>2 kW at power factor 0.8 lagging.<\/td><\/tr><tr><td>6 pm to 1 am<\/td><td>5 kW at power factor 0.9 lagging<em>.<\/em><\/td><\/tr><tr><td>1 am to 7 am<\/td><td>No-load<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p id=\"para-787\">Determine the all-day efficiency.<\/p>\n\n\n\n<p id=\"para-788\"><strong>(P.T.U., Dec. 2006)<\/strong><\/p>\n\n\n\n<p id=\"para-789\"><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-790\">Transformer rating = 5 kVA;&nbsp;<em>P<\/em><sub>i<\/sub>&nbsp;= 50 W;&nbsp;<em>P<\/em><sub>c<\/sub>&nbsp;= 100 W<\/p>\n\n\n\n<p id=\"para-791\">Load variation in tabulated form is given below:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page549_3.png\" alt=\"img\"\/><\/figure>\n\n\n\n<p id=\"para-792\">kWh output in 24 h = 3 \u00d7 6 + 2 \u00d7 5 + 5 \u00d7 7 + 0 \u00d7 6 = 63 kWh<\/p>\n\n\n\n<p id=\"para-793\">Iron losses in 24 h =&nbsp;<em>P<\/em><sub>i&nbsp;<\/sub>in kW \u00d7 24 =&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page549_4.png\" alt=\"img\" width=\"209\" height=\"66\"><\/p>\n\n\n\n<p id=\"para-794\">Copper losses in 24 h =&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page549_5.png\" alt=\"img\" width=\"636\" height=\"65\"><\/p>\n\n\n\n<p>= 0.6 + 0.125 + 0.8625 + 0 = 1.5875 kWh<\/p>\n\n\n\n<p id=\"para-795\">All-day efficiency,&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page549_6.png\" alt=\"img\" width=\"690\" height=\"68\"><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page549_7.png\" alt=\"img\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The efficiency discussed so far is the ordinary or commercial efficiency which is given by the ratio of output power to input power, that is, Commercial efficiency, The load on certain transformers fluctuate throughout the day. The distribution transformers are energized for 24 h, but they deliver very light loads for major portion of the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":2841,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[413],"tags":[],"class_list":["post-2873","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-single-phase-transformers"],"jetpack_featured_media_url":"https:\/\/workhouse.sweetdishy.com\/wp-content\/uploads\/2024\/08\/power-transformer.png","_links":{"self":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/2873","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/comments?post=2873"}],"version-history":[{"count":1,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/2873\/revisions"}],"predecessor-version":[{"id":2874,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/2873\/revisions\/2874"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media\/2841"}],"wp:attachment":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media?parent=2873"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/categories?post=2873"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/tags?post=2873"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}