{"id":2904,"date":"2024-08-25T20:57:27","date_gmt":"2024-08-25T20:57:27","guid":{"rendered":"https:\/\/workhouse.sweetdishy.com\/?p=2904"},"modified":"2024-08-25T20:57:28","modified_gmt":"2024-08-25T20:57:28","slug":"frequency-of-rotor-currents","status":"publish","type":"post","link":"https:\/\/workhouse.sweetdishy.com\/index.php\/2024\/08\/25\/frequency-of-rotor-currents\/","title":{"rendered":"FREQUENCY OF ROTOR CURRENTS"},"content":{"rendered":"\n<p id=\"para-056\">The frequency of rotor currents depends upon the relative speed between rotor and stator field. When the rotor is stationary, the frequency of rotor currents is the same as that of the supply frequency. But once the rotor starts to rotate, the frequency of rotor currents depends upon slip speed (<em>N<\/em><sub>s<\/sub>\u2212<em>&nbsp;N<\/em>). Let at any speed&nbsp;<em>N<\/em>, the frequency of rotor currents be&nbsp;<em>f<\/em><sub>r<\/sub>.<\/p>\n\n\n\n<p id=\"para-057\">Then,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page645_2.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-058\"><strong>Example 12.1<\/strong><\/p>\n\n\n\n<p id=\"para-059\">A three-phase, four-pole, 50 Hz, induction motor runs at 1460 rpm. Determine its percentage slip.<\/p>\n\n\n\n<p id=\"para-060\"><strong>(U.P.T.U. June 2004)<\/strong><\/p>\n\n\n\n<p id=\"para-061\"><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-062\">Synchronous speed,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page645_3.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-063\">Speed of motor,<\/p>\n\n\n\n<p id=\"para-064\">&nbsp;<\/p>\n\n\n\n<p><em>N&nbsp;<\/em>= 1460 rpm<\/p>\n\n\n\n<p id=\"para-065\">Slip,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page645_4.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p>= 2.667%<\/p>\n\n\n\n<p id=\"para-066\"><strong>Example 12.2<\/strong><\/p>\n\n\n\n<p id=\"para-067\">In a three-phase slip-ring, four-pole induction motor, the rotor frequency is found to be 2.0 Hz, while connected to a 400 V, three-phase, 50 Hz supply. Determine motor speed in rpm.<\/p>\n\n\n\n<p id=\"para-068\">(<strong>U.P.T.U. Dec. 2003<\/strong>)<\/p>\n\n\n\n<p id=\"para-069\"><a><\/a><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-070\">Synchronous speed,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page646_1.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-071\">Slip,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page646_2.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-072\">Speed of motor on load,&nbsp;<em>N&nbsp;<\/em>=&nbsp;<em>N<\/em><sub>S<\/sub>&nbsp;(1 \u2212&nbsp;<em>S<\/em>) = 1500 (1 \u2212 0.04) = 1440 rpm<\/p>\n\n\n\n<p id=\"para-073\"><strong>Example 12.3<\/strong><\/p>\n\n\n\n<p id=\"para-074\">A three-phase, four-pole induction motor is supplied from three-phase, 50 Hz AC supply. Calculate (i) synchronous speed, (ii) rotor speed when slip is 4%, and (iii) rotor frequency when rotor runs at 600 rpm.<\/p>\n\n\n\n<p id=\"para-075\"><strong>(U.P.T.U. 2005\u201306)<\/strong><\/p>\n\n\n\n<p id=\"para-076\"><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-077\">Here,&nbsp;<em>P&nbsp;<\/em>= 4;&nbsp;<em>f&nbsp;<\/em>= 50 Hz;&nbsp;<em>S&nbsp;<\/em>= 4% = 0.04<\/p>\n\n\n\n<ol class=\"wp-block-list\" id=\"ol-005\">\n<li>Synchronous speed,&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page646_3.png\" alt=\"image\" width=\"297\" height=\"49\"><\/li>\n\n\n\n<li>Rotor speed,&nbsp;<em>N&nbsp;<\/em>=&nbsp;<em>N<\/em><sub>S<\/sub>&nbsp;\u00d7 (1 \u2212&nbsp;<em>S<\/em>) = 1500 \u00d7 (1 \u2212 0.04) = 1440 rpm<\/li>\n\n\n\n<li>When rotor speed is 600 rpm<\/li>\n<\/ol>\n\n\n\n<p id=\"para-078\">Slip,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page646_4.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-079\">Rotor frequency,<\/p>\n\n\n\n<p id=\"para-080\">&nbsp;<\/p>\n\n\n\n<p><em>f<\/em><sub>r<\/sub>&nbsp;=&nbsp;<em>S&nbsp;<\/em>\u00d7<em>&nbsp;f&nbsp;<\/em>= 0.6 \u00d7 50 = 30Hz<\/p>\n\n\n\n<p id=\"para-081\"><strong>Example 12.4<\/strong><\/p>\n\n\n\n<p id=\"para-082\">A three-phase slip-ring, four-pole induction motor has rotor frequency 2.0 Hz while connected to 400 V, three-phase, 50 Hz supply. Determine slip and rotor speed.<\/p>\n\n\n\n<p id=\"para-083\"><strong>(U.P.T.U. 2006\u201307)<\/strong><\/p>\n\n\n\n<p id=\"para-084\"><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-085\">No. of poles,&nbsp;<em>P&nbsp;<\/em>= 4<\/p>\n\n\n\n<p id=\"para-086\">Supply frequency,&nbsp;<em>f&nbsp;<\/em>= 50 Hz<\/p>\n\n\n\n<p id=\"para-087\">Rotor frequency,&nbsp;<em>\u0192<\/em><sub>r<\/sub>&nbsp;= 2 Hz<\/p>\n\n\n\n<p id=\"para-088\">Now,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page646_5.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-089\">Synchronous speed,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page646_6.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-090\">Rotor speed,<\/p>\n\n\n\n<p id=\"para-091\">&nbsp;<\/p>\n\n\n\n<p><em>N&nbsp;<\/em>=&nbsp;<em>N<\/em><sub>S<\/sub>&nbsp;\u00d7 (1 \u2212&nbsp;<em>S<\/em>) = 1500 \u00d7 (1 \u2212 0.04) = 1440 rpm<\/p>\n\n\n\n<p id=\"para-092\"><strong>Example 12.5<\/strong><\/p>\n\n\n\n<p id=\"para-093\">A three-phase, four-pole induction motor operates from a supply whose frequency is 50 Hz. Calculate its synchronous speed, speed of rotor when slip is 0.04 and frequency of rotor currents at standstill.<\/p>\n\n\n\n<p id=\"para-094\"><strong>(U.P.T.U. 2004\u201305)<\/strong><\/p>\n\n\n\n<p id=\"para-095\"><a><\/a><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-096\">Synchronous speed,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page647_1.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-097\">Speed of rotor when the slip is 0.04<\/p>\n\n\n\n<p id=\"para-098\">&nbsp;<\/p>\n\n\n\n<p><em>N&nbsp;<\/em>= (1 \u2212&nbsp;<em>S<\/em>) \u00d7&nbsp;<em>N<\/em><sub>s<\/sub>= (1 \u2212 0.04) \u00d7 1500 = 1440 rpm<\/p>\n\n\n\n<p id=\"para-099\">Frequency of rotor currents at standstill<\/p>\n\n\n\n<p id=\"para-100\">At standstill =&nbsp;<em>S&nbsp;<\/em>= 1 and&nbsp;<em>N&nbsp;<\/em>= 0<\/p>\n\n\n\n<p id=\"para-101\">\u2234<\/p>\n\n\n\n<p id=\"para-102\">&nbsp;<\/p>\n\n\n\n<p>Frequency of rotor current&nbsp;<em>\u0192<\/em><sub>r<\/sub>&nbsp;=&nbsp;<em>S<\/em>&nbsp;\u00d7<em>&nbsp;f&nbsp;<\/em>= 1 \u00d7 50 = 50Hz<\/p>\n\n\n\n<p id=\"para-103\"><strong>Example 12.6<\/strong><\/p>\n\n\n\n<p id=\"para-104\">A 12-pole, three-phase alternator driven at a speed of 500 rpm supplies power to an eight-pole, three-phase induction motor. If the slip of the motor is 0.03 pu, then calculate the speed.<\/p>\n\n\n\n<p id=\"para-105\"><strong>(U.P.T.U. July 2002)<\/strong><\/p>\n\n\n\n<p id=\"para-106\"><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-107\">No. of poles of the alternator,&nbsp;<em>P<\/em><sub>a<\/sub>= 12<\/p>\n\n\n\n<p id=\"para-108\">Speed of alternator,&nbsp;<em>N<\/em><sub>a<\/sub>= 500 rpm<\/p>\n\n\n\n<p id=\"para-109\">No. of poles of the induction motor,&nbsp;<em>P<\/em><sub>m<\/sub>= 8; slip&nbsp;<em>S&nbsp;<\/em>= 0.03 pu<\/p>\n\n\n\n<p id=\"para-110\">Supply frequency delivered by the alternator,&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page647_2.png\" alt=\"image\" width=\"248\" height=\"49\"><\/p>\n\n\n\n<p id=\"para-111\">Synchronous speed of three-phase induction motor,&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page647_3.png\" alt=\"image\" width=\"276\" height=\"54\"><\/p>\n\n\n\n<p id=\"para-112\">Speed of three-phase induction motor,&nbsp;<em>N&nbsp;<\/em>=&nbsp;<em>N<\/em><sub>S<\/sub>&nbsp;\u00d7 (1 \u2212&nbsp;<em>S<\/em>) = 750 \u00d7 (1 \u2212 0.03) = 727.5 rpm<\/p>\n\n\n\n<p id=\"para-113\"><strong>Example 12.7<\/strong><\/p>\n\n\n\n<p id=\"para-114\">A 12-pole, three-phase alternator is coupled to an engine running at 500 rpm. It supplied a three-phase induction motor having a full-load speed of 1440 rpm. Find the percentage slip, frequency of rotor current and number of poles of the motor.<\/p>\n\n\n\n<p id=\"para-115\"><strong>(U.P.T.U. 2005\u201306)<\/strong><\/p>\n\n\n\n<p id=\"para-116\"><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-117\">No. of poles of three-phase alternator,&nbsp;<em>P<\/em><sub>a<\/sub>= 12<\/p>\n\n\n\n<p id=\"para-118\">Speed of engine,&nbsp;<em>N<\/em><sub>S(a)<\/sub>&nbsp;= 500 rpm<\/p>\n\n\n\n<p id=\"para-119\">Frequency of generated voltage,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page647_4.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-120\">For three-phase induction motor,<\/p>\n\n\n\n<p id=\"para-121\">Synchronous speed,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page647_5.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-122\"><em>N<\/em><sub>S<\/sub>&nbsp;in nearly equal to&nbsp;<em>N<\/em><\/p>\n\n\n\n<p id=\"para-123\"><a><\/a>\u2234<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page648_1.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-124\">But poles are always even in number<\/p>\n\n\n\n<p id=\"para-125\">\u2234<\/p>\n\n\n\n<p id=\"para-126\">&nbsp;<\/p>\n\n\n\n<p><em>P<\/em><sub>m<\/sub>= 4<\/p>\n\n\n\n<p id=\"para-127\">\u2234 Synchronous speed,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page648_2.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-128\">Slip<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page648_3.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-129\">Frequency of rotor current,&nbsp;<em>f<\/em><sub>r<\/sub>&nbsp;=&nbsp;<em>S<\/em>&nbsp;\u00d7&nbsp;<em>f&nbsp;<\/em>= 0.04 \u00d7 50 = 2Hz<\/p>\n\n\n\n<p id=\"para-130\"><strong>Example 12.8<\/strong><\/p>\n\n\n\n<p id=\"para-131\">A motor-generator set used for providing variable frequency AC supply consists of a three-phase, 10-pole synchronous motor and a 24-pole, three-phase synchronous generator. The motor- generator set is fed from a 25 Hz, three-phase AC supply. A six-pole, three-phase induction motor is electrically connected to the terminals of the synchronous generator and runs at a slip of 5%. Determine (i) the frequency of the generated voltage of the synchronous generator, (ii) the speed at which the induction motor is running.<\/p>\n\n\n\n<p id=\"para-132\"><strong>(U.P.T.U. Feb. 2001)<\/strong><\/p>\n\n\n\n<p id=\"para-133\"><em>Solution:<\/em><\/p>\n\n\n\n<p id=\"para-134\">Given, No. of poles of synchronous motor,&nbsp;<em>P<\/em><sub>sm<\/sub>= 10<\/p>\n\n\n\n<p id=\"para-135\">No. of poles of synchronous generator,&nbsp;<em>P<\/em><sub>sg<\/sub>&nbsp;= 24<\/p>\n\n\n\n<p id=\"para-136\">No. of poles of induction motor,&nbsp;<em>P<\/em><sub>im<\/sub>&nbsp;= 6<\/p>\n\n\n\n<p id=\"para-137\">Supply frequency,&nbsp;<em>f<\/em>&nbsp;= 25 Hz<\/p>\n\n\n\n<p id=\"para-138\">Slip of induction motor,&nbsp;<em>S&nbsp;<\/em>= 5% = 0.05<\/p>\n\n\n\n<p id=\"para-139\">Speed of synchronous motor,&nbsp;<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page648_4.png\" alt=\"image\" width=\"295\" height=\"55\"><\/p>\n\n\n\n<p id=\"para-140\">Frequency of emf generated by synchronous generator,<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page648_5.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-141\">Synchronous speed of the induction motor (revolution field),<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9789332558311\/files\/images\/page646_6.png\" alt=\"image\"\/><\/figure>\n\n\n\n<p id=\"para-142\">Running speed of the induction motor,<\/p>\n\n\n\n<p id=\"para-143\">&nbsp;<\/p>\n\n\n\n<p><em>N&nbsp;<\/em>=&nbsp;<em>N<\/em><sub>s<\/sub>&nbsp;\u00d7 (1 \u2212&nbsp;<em>S<\/em>) = 1200 \u00d7 (1 \u2212 0.05) = 1140 rpm<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The frequency of rotor currents depends upon the relative speed between rotor and stator field. When the rotor is stationary, the frequency of rotor currents is the same as that of the supply frequency. But once the rotor starts to rotate, the frequency of rotor currents depends upon slip speed (Ns\u2212&nbsp;N). Let at any speed&nbsp;N, [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":2894,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[415],"tags":[],"class_list":["post-2904","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-three-phase-induction-motors"],"jetpack_featured_media_url":"https:\/\/workhouse.sweetdishy.com\/wp-content\/uploads\/2024\/08\/spare-parts.png","_links":{"self":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/2904","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/comments?post=2904"}],"version-history":[{"count":1,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/2904\/revisions"}],"predecessor-version":[{"id":2905,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/2904\/revisions\/2905"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media\/2894"}],"wp:attachment":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media?parent=2904"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/categories?post=2904"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/tags?post=2904"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}