{"id":3161,"date":"2024-08-26T22:14:27","date_gmt":"2024-08-26T22:14:27","guid":{"rendered":"https:\/\/workhouse.sweetdishy.com\/?p=3161"},"modified":"2024-08-26T22:14:27","modified_gmt":"2024-08-26T22:14:27","slug":"gain","status":"publish","type":"post","link":"https:\/\/workhouse.sweetdishy.com\/index.php\/2024\/08\/26\/gain\/","title":{"rendered":"Gain"},"content":{"rendered":"\n

In the case of an amplifier system we might have the output directly proportional to the input and, with a gain of 10, if we have an input of a 1 V signal we can calculate that the output will be ten times greater and so 10 V. In general, for such a system where the output is directly proportional to the input, we can write:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n

with G<\/em> being the gain.<\/p>\n\n\n\n

Example 18.1<\/h5>\n\n\n\n

A motor has an output speed which is directly proportional to the voltage applied to its armature. If the output is 5 rev\/s when the input voltage is 2 V, what is the system gain?<\/p>\n\n\n\n

Solution<\/h5>\n\n\n\n

With output=G\u00d7input, then G<\/em>=5\/2=2.5 (rev\/s)\/V.<\/p>\n\n\n\n

18.9.1 Gain of Systems in Series<\/h3>\n\n\n\n

Consider two systems, such as amplifiers, in series with the first having a gain\u00a0G<\/em>1<\/sub>\u00a0and the second a gain\u00a0G<\/em>2<\/sub>\u00a0(Figure 18.80(a)). The first system has an input of\u00a0x<\/em>1<\/sub>\u00a0and an output of\u00a0y<\/em>2<\/sub>\u00a0and thus:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n
\"image\"\/<\/figure>\n\n\n\n
\"image\"\/<\/figure>\n\n\n\n

Figure 18.80<\/strong> (a) Two systems in series; (b) the equivalent system with a gain equal to the product of the gains of the two constituent systems<\/p>\n\n\n\n

The second system has an input of y<\/em>1<\/sub> and an output of y<\/em>2<\/sub> and thus:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n

The overall system has an input of x<\/em>1<\/sub> and an output of y<\/em>2<\/sub> and thus, if we represent the overall system as having a gain of G<\/em>:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n

and so:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n

Thus:<\/p>\n\n\n\n

For series-connected systems, the overall gain is the product of the gains of the constituent systems.<\/p>\n\n\n\n

Example 18.2<\/h5>\n\n\n\n

A system consists of an amplifier with a gain of 10 providing the armature voltage for a motor which gives an output speed which is proportional to the armature voltage, the constant of proportionality being 5 (rev\/s)\/V. What is the relationship between the input voltage to the system and the output motor speed?<\/p>\n\n\n\n

Solution<\/h5>\n\n\n\n

The overall gain G<\/em>=G<\/em>1<\/sub>\u00d7G<\/em>2<\/sub>=10\u00d75=50 rev\/s)\/V.<\/p>\n\n\n\n

18.9.2 Feedback Loops<\/h3>\n\n\n\n

Consider a system with negative feedback (Figure 18.81). The output of the system is fed back via a measurement system with a gain\u00a0H<\/em>\u00a0to subtract from the input to a system with gain\u00a0G<\/em>.<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n

Figure 18.81<\/strong> System with negative feedback: the fed back signal subtracts from the input<\/p>\n\n\n\n

The input to the feedback system is y and thus its output, i.e., the feedback signal, is Hy.<\/em> The error is x<\/em>–Hy.<\/em> Hence, the input to the G<\/em> system is x<\/em>–Hy<\/em> and its output y<\/em>. Thus:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n

and so:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n

The overall input of the system is y<\/em> for an input x<\/em> and so the overall gain G<\/em> of the system is y\/x.<\/em> Hence:<\/p>\n\n\n\n

system gain \"image\"<\/p>\n\n\n\n

For a system with a negative feedback, the overall gain is the forward path gain divided by one plus the product of the forward path and feedback path gains.<\/em><\/p>\n\n\n\n

For a system with positive feedback (Figure 18.82), i.e., the fed back signal adds to the input signal, the feedback signal is\u00a0Hy<\/em>\u00a0and thus the input to the\u00a0G<\/em>\u00a0system is\u00a0x<\/em>+Hy.<\/em>\u00a0Hence:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n

and so:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n
\"image\"\/<\/figure>\n\n\n\n

Figure 18.82<\/strong> System with positive feedback: the fed back signal adds to the input<\/p>\n\n\n\n

system gain \"image\"<\/a><\/p>\n\n\n\n

For a system with a positive feedback, the overall gain is the forward path gain divided by one minus the product of the forward path and feedback path gains.<\/em><\/p>\n\n\n\n

Example 18.3<\/h5>\n\n\n\n

A negative feedback system has a forward path gain of 12 and a feedback path gain of 0.1. What is the overall gain of the system?<\/p>\n\n\n\n

Solution<\/h5>\n\n\n\n

System gain \"image\"<\/p>\n\n\n\n

18.9.3 The Feedback Amplifier<\/h3>\n\n\n\n

Figure 18.83\u00a0shows the circuit of a basic feedback amplifier. It consists of an operational amplifier with a potential divider of two resistors R1<\/sub>\u00a0and R2<\/sub>\u00a0connected across its output. The output from this potential divider is fed back to the inverting input of the amplifier. The input to the amplifier is via its noninverting input. Thus the sum of the inverted feedback input and the noninverted input is the error signal. The op-amp has a very high voltage gain G. Thus\u00a0GH, H<\/em>\u00a0being the gain of the feedback loop, is very large compared with 1 and so the overall system gain is:<\/p>\n\n\n\n

\"image\"\/<\/figure>\n\n\n\n

Figure 18.83<\/strong> Feedback amplifier<\/p>\n\n\n\n

system gain \"image\"<\/a><\/p>\n\n\n\n

Since the gain G<\/em> of the op-amp can be affected by changes in temperature, aging, etc. and thus can vary, the use of the op-amp with a feedback loop means that, since H is just made up of resistances which are likely to be more stable, a more stable amplifier system is produced. The feedback loop gain H is the fraction of the output signal fed back and so is R<\/em>1<\/sub>\/(R<\/em>1<\/sub>+R<\/em>2<\/sub>).<\/em> Hence, the overall gain of the system is:<\/p>\n\n\n\n

system gain \"image\"<\/p>\n\n\n\n

Example 18.4<\/h5>\n\n\n\n

What is the overall gain of a noninverting feedback op-amp, connected as in\u00a0Figure 18.83, if the op-amp has a voltage gain of 200,000,\u00a0R<\/em>1<\/sub>=1\u00a0k\u03a9 and\u00a0R<\/em>2<\/sub>=49\u00a0k\u03a9?<\/p>\n\n\n\n

Solution<\/h5>\n\n\n\n

The overall system gain is independent of the voltage gain of the op-amp and is given by (R<\/em>1<\/sub>+R<\/em>2<\/sub>)\/R<\/em>1<\/sub>=50\/1=50.<\/p>\n","protected":false},"excerpt":{"rendered":"

In the case of an amplifier system we might have the output directly proportional to the input and, with a gain of 10, if we have an input of a 1 V signal we can calculate that the output will be ten times greater and so 10 V. In general, for such a system where the output […]<\/p>\n","protected":false},"author":1,"featured_media":3162,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[423],"tags":[],"class_list":["post-3161","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-control-and-instrumentation-systems"],"jetpack_featured_media_url":"https:\/\/workhouse.sweetdishy.com\/wp-content\/uploads\/2024\/08\/gain.png","_links":{"self":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/3161","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/comments?post=3161"}],"version-history":[{"count":1,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/3161\/revisions"}],"predecessor-version":[{"id":3163,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/3161\/revisions\/3163"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media\/3162"}],"wp:attachment":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media?parent=3161"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/categories?post=3161"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/tags?post=3161"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}