{"id":3999,"date":"2024-09-19T13:35:20","date_gmt":"2024-09-19T13:35:20","guid":{"rendered":"https:\/\/workhouse.sweetdishy.com\/?p=3999"},"modified":"2024-09-24T09:04:28","modified_gmt":"2024-09-24T09:04:28","slug":"introduction-to-quantum-physics-and-information-processing-3","status":"publish","type":"post","link":"https:\/\/workhouse.sweetdishy.com\/index.php\/2024\/09\/19\/introduction-to-quantum-physics-and-information-processing-3\/","title":{"rendered":"Introduction to Quantum Physics and Information Processing"},"content":{"rendered":"\n<p>De\ufb01nition 3.1. The tensor product of two matrices A of dimensions m \u00d7 n<\/p>\n\n\n\n<p>and B of any dimensions is given by<\/p>\n\n\n\n<p>A \u2297 B =<\/p>\n\n\n\n<p>\uf8ee<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8f0<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>B A<\/p>\n\n\n\n<p>12<\/p>\n\n\n\n<p>B . . . A<\/p>\n\n\n\n<p>1n<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>21<\/p>\n\n\n\n<p>B A<\/p>\n\n\n\n<p>22<\/p>\n\n\n\n<p>B . . . A<\/p>\n\n\n\n<p>2n<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>m1<\/p>\n\n\n\n<p>B A<\/p>\n\n\n\n<p>m2<\/p>\n\n\n\n<p>B . . . A<\/p>\n\n\n\n<p>mn<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>\uf8f9<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fb<\/p>\n\n\n\n<p>. (3.31)<\/p>\n\n\n\n<p>Thus we have<\/p>\n\n\n\n<p>|00i =<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>\u2297<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>\uf8ee<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8f0<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>\uf8f9<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fb<\/p>\n\n\n\n<p>; |01i =<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>\u2297<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>\uf8ee<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8f0<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>\uf8f9<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fb<\/p>\n\n\n\n<p>;<\/p>\n\n\n\n<p>|10i =<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>\u2297<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>\uf8ee<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8f0<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>\uf8f9<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fb<\/p>\n\n\n\n<p>; |11i =<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>\u2297<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>\uf8ee<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8f0<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>\uf8f9<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fb<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>(3.32)<\/p>\n\n\n\n<p>Thus we have the natural basis for the 4-dimensional vector space from those<\/p>\n\n\n\n<p>of two 2-dimensional spaces.<\/p>\n\n\n\n<p>Example 3.5.1. Direct products: to express \u03c3<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>on a 2-qubit state as a matrix,<\/p>\n\n\n\n<p>we take the direct product of two \u03c3<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>s acting on each single qubit state:<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>\u2297 \u03c3<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>0 1<\/p>\n\n\n\n<p>1 0<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>\u2297<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>0 1<\/p>\n\n\n\n<p>1 0<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>\uf8ee<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8ef<\/p>\n\n\n\n<p>\uf8f0<\/p>\n\n\n\n<p>0 0 0 1<\/p>\n\n\n\n<p>0 0 1 0<\/p>\n\n\n\n<p>0 1 0 0<\/p>\n\n\n\n<p>1 0 0 0<\/p>\n\n\n\n<p>\uf8f9<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fa<\/p>\n\n\n\n<p>\uf8fb<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>We can generalize to n qubits: the natural basis of the n-qubit Hilbert<\/p>\n\n\n\n<p>space H<\/p>\n\n\n\n<p>\u2297n<\/p>\n\n\n\n<p>consists of 2<\/p>\n\n\n\n<p>n<\/p>\n\n\n\n<p>orthogonal vectors<\/p>\n\n\n\n<p>{|0i, |1i, |2i, &#8230;, |2<\/p>\n\n\n\n<p>n<\/p>\n\n\n\n<p>\u2212 1i}. (3.33)<\/p>\n\n\n\n<p>The interpretation as an n-bit register is straightforward when the labels are<\/p>\n\n\n\n<p>written in binary. For example, the 8<\/p>\n\n\n\n<p>th<\/p>\n\n\n\n<p>basis vector for a 4-qubit Hilbert space<\/p>\n\n\n\n<p>will be<\/p>\n\n\n\n<p>|7i = |0111i = |0i \u2297 |1i \u2297 |1i \u2297 |1i.<\/p>\n\n\n\n<p>The algebra of multi-qubit states generalizes in a natural manner from<\/p>\n\n\n\n<p>that of single qubits.<\/p>\n\n\n\n<p><\/p>\n\n\n\n<p>Problems 59<\/p>\n\n\n\n<p>Box 3.8: Algebra of Tensor Product States<\/p>\n\n\n\n<p>Consider two distinct physical systems A and B with Hilbert spaces H<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>of dimensions 2<\/p>\n\n\n\n<p>n<\/p>\n\n\n\n<p>and H<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>of dimensions 2<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>. Let the basis vectors of these two<\/p>\n\n\n\n<p>spaces be denoted {|i<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i}, i<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>= 0, 1, &#8230;2<\/p>\n\n\n\n<p>n<\/p>\n\n\n\n<p>\u22121, and {|\u00b5<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i}, \u00b5<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>= 0, 1, &#8230;2<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>\u22121.<\/p>\n\n\n\n<p>If I pick a state |\u03c6<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i from A and a state |\u03c8<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i from B, I can form a state in<\/p>\n\n\n\n<p>the tensor product Hilbert space H<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>= H<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>\u2297 H<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>as<\/p>\n\n\n\n<p>|\u03a6<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>i = |\u03c6<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i|\u03c8<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i.<\/p>\n\n\n\n<p>\u2022 Probability amplitude hi<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>, \u00b5<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>|\u03a6i = hi<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>|\u03c6<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>ih\u00b5<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>|\u03c8<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u2022 Inner product h\u03a6<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>|\u03a6<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i = h\u03c6<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>|\u03c6<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>ih\u03c8<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>|\u03c8<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u2022 Basis states for H<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>is the set of product basis vectors {|\u03c5<\/p>\n\n\n\n<p>i\u00b5<\/p>\n\n\n\n<p>i =<\/p>\n\n\n\n<p>|i<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i|\u00b5<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i}<\/p>\n\n\n\n<p>\u2022 The most general state in H<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>is a linear combination of these basis<\/p>\n\n\n\n<p>states:<\/p>\n\n\n\n<p>|\u03a8i<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>i\u00b5<\/p>\n\n\n\n<p>C<\/p>\n\n\n\n<p>i\u00b5<\/p>\n\n\n\n<p>|\u03c5<\/p>\n\n\n\n<p>i\u00b5<\/p>\n\n\n\n<p>i.<\/p>\n\n\n\n<p>\u2022 If two operators<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>A and<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>B act on each space independently then the<\/p>\n\n\n\n<p>action on the product space is given by the operator<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>C =<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>A \u2297<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>B.<\/p>\n\n\n\n<p>Summary: The Math and the Physics<\/p>\n\n\n\n<p>The arena of quantum mechanics is the Hilbert space H, the state vectors<\/p>\n\n\n\n<p>live here, and transformations of the state vector are operators in H. To be able<\/p>\n\n\n\n<p>to work e\ufb03ciently with the maths, we summarize the correspondence between<\/p>\n\n\n\n<p>the mathematical concept and the physical quantities in Table 3.2. Note that<\/p>\n\n\n\n<p>this is for \u201cpure\u201d states of isolated quantum systems. (We will discuss mixed<\/p>\n\n\n\n<p>states of systems that are in\ufb02uenced by some environment in a later chapter.)<\/p>\n\n\n\n<p>Problems<\/p>\n\n\n\n<p>3.1. Prove that a Hermitian matrix has real eigenvalues and its eigenvectors<\/p>\n\n\n\n<p>corresponding to distinct eigenvalues are orthogonal to each other.<\/p>\n\n\n\n<p>3.2. Prove that a unitary matrix has complex eigenvalues of unit magnitude, and<\/p>\n\n\n\n<p>that its eigenvectors corresponding to distinct eigenvalues are orthogonal.<\/p>\n\n\n\n<p><\/p>\n\n\n\n<p>60 Introduction to Quantum Physics and Information Processing<\/p>\n\n\n\n<p>TABLE 3.2: Correspondence between the math and the physics of quantum<\/p>\n\n\n\n<p>mechanics.<\/p>\n\n\n\n<p>Math Physics<\/p>\n\n\n\n<p>Normalized vector |\u03c8i \u2208 H pure state<\/p>\n\n\n\n<p>Hermitian operator<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>A on H physical observable<\/p>\n\n\n\n<p>Eigenvalues {a<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>} of<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>A set of all possible values obtainable on measur-<\/p>\n\n\n\n<p>ing the observable A<\/p>\n\n\n\n<p>Eigenvector |a<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>i of<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>A state in which measuring A gives a value a<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>Computational basis {|ii},<\/p>\n\n\n\n<p>i = 0, 1, 2&#8230;<\/p>\n\n\n\n<p>eigenstates of a suitable \ufb01ducial observable<\/p>\n\n\n\n<p>Inner product hi|\u03c8i probability amplitude for the state |\u03c8i to be in<\/p>\n\n\n\n<p>the basis state |ii<\/p>\n\n\n\n<p>Amplitude squared |ha<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>|\u03c8i|<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>probability of obtaining the value a<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>on mea-<\/p>\n\n\n\n<p>suring A in the state \u03c8<\/p>\n\n\n\n<p>Matrix element A<\/p>\n\n\n\n<p>ij<\/p>\n\n\n\n<p>= hi|A|ji amplitude for producing a transition from |ji<\/p>\n\n\n\n<p>to |ii by the action of A (No assumption is<\/p>\n\n\n\n<p>made here about the nature of the operation)<\/p>\n\n\n\n<p>Diagonal element h\u03c8|A|\u03c8i average value of the observable A in the state<\/p>\n\n\n\n<p>|\u03c8i<\/p>\n\n\n\n<p>Unitary operator<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>U possible evolution operator that changes the<\/p>\n\n\n\n<p>state reversibly<\/p>\n\n\n\n<p>3.3. Show that if<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>H is a Hermitian operator then e<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>H<\/p>\n\n\n\n<p>is a unitary operator.<\/p>\n\n\n\n<p>3.4. Given a unitary operator<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>U, show that the operator i( +<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>U)( \u2212<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>U) is<\/p>\n\n\n\n<p>Hermitian.<\/p>\n\n\n\n<p>3.5. For a Hermitian or unitary matrix, show that the sum of diagonal elements<\/p>\n\n\n\n<p>(the trace) equals the sum of the eigenvalues, and the determinant equals<\/p>\n\n\n\n<p>the product of the eigenvalues.<\/p>\n\n\n\n<p>3.6. For each of the following matrices, \ufb01nd if they are unitary or Hermitian or<\/p>\n\n\n\n<p>neither. Find their eigenvalues and eigenvectors. Find if their eigenvectors<\/p>\n\n\n\n<p>are orthogonal.<\/p>\n\n\n\n<p>(a)<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>1 i<\/p>\n\n\n\n<p>i \u22121<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p>(b)<\/p>\n\n\n\n<p>&#8220;<\/p>\n\n\n\n<p>0 1<\/p>\n\n\n\n<p>0 0<\/p>\n\n\n\n<p>#<\/p>\n\n\n\n<p><\/p>\n\n\n\n<p>Problems 61<\/p>\n\n\n\n<p>3.7. For the three Pauli matrices \u03c3<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>, \u03c3<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>, and \u03c3<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>,<\/p>\n\n\n\n<p>(a) Show that \u03c3<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>= .<\/p>\n\n\n\n<p>(b) Show that \u03c3<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u2019s are Hermitian as well as unitary.<\/p>\n\n\n\n<p>(c) Find the commutator [\u03c3<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>, \u03c3<\/p>\n\n\n\n<p>j<\/p>\n\n\n\n<p>] = \u03c3<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>j<\/p>\n\n\n\n<p>\u2212 \u03c3<\/p>\n\n\n\n<p>j<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>(d) Find the anti-commutator {\u03c3<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>, \u03c3<\/p>\n\n\n\n<p>j<\/p>\n\n\n\n<p>} = \u03c3<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>j<\/p>\n\n\n\n<p>+ \u03c3<\/p>\n\n\n\n<p>j<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>3.8. Show that all the eigenvalues of any projection operator are either 1 or 0.<\/p>\n\n\n\n<p>3.9. Show that the operator which performs a transformation from the Z basis<\/p>\n\n\n\n<p>to the X basis has the following matrix representation:<\/p>\n\n\n\n<p>H =<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>\u221a<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>1 1<\/p>\n\n\n\n<p>1 \u22121<\/p>\n\n\n\n<p>!<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>This operator is also known as the Hadamard operator and is very useful in<\/p>\n\n\n\n<p>quantum computation.<\/p>\n\n\n\n<p>Verify that this operator is Hermitian. Show that it can be expressed as a<\/p>\n\n\n\n<p>linear combination of the Pauli matrices.<\/p>\n\n\n\n<p>3.10. Show that for any two operators A and B,<\/p>\n\n\n\n<p>AB =<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>[A, B] +<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>{A, B}.<\/p>\n\n\n\n<p>3.11. Given a unit vector \u02c6e = (e<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>, e<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>, e<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>) in an arbitrary direction, we can de\ufb01ne<\/p>\n\n\n\n<p>the component of spin along \u02c6e by<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>e<\/p>\n\n\n\n<p>= e<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>+ e<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>+ e<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>(a) Show that \u03c3<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>e<\/p>\n\n\n\n<p>= .<\/p>\n\n\n\n<p>(b) Find the eigenvalues and eigenvectors of \u03c3<\/p>\n\n\n\n<p>e<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>3.12. De\ufb01ne a \u201cvector matrix\u201d ~\u03c3 =<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>i\u03c3<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>+<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>j\u03c3<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>+<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>k\u03c3<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>. Show that<\/p>\n\n\n\n<p>(~a. \u00b7 ~\u03c3)(<\/p>\n\n\n\n<p>~<\/p>\n\n\n\n<p>b \u00b7 ~\u03c3) = (~a \u00b7<\/p>\n\n\n\n<p>~<\/p>\n\n\n\n<p>b) + i(~a \u00d7<\/p>\n\n\n\n<p>~<\/p>\n\n\n\n<p>b) \u00b7 ~\u03c3 (3.34)<\/p>\n\n\n\n<p>for vectors ~a and<\/p>\n\n\n\n<p>~<\/p>\n\n\n\n<p>b.<\/p>\n\n\n\n<p>3.13. Find the expectation value of \u03c3<\/p>\n\n\n\n<p>e<\/p>\n\n\n\n<p>in the state |0i. Generalize this result<\/p>\n\n\n\n<p>to \ufb01nd the expectation value of \u03c3<\/p>\n\n\n\n<p>e<\/p>\n\n\n\n<p>in a state |<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>f+i where<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>f is a general<\/p>\n\n\n\n<p>direction making angle \u03b8 with the \u02c6z axis.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>De\ufb01nition 3.1. The tensor product of two matrices A of dimensions m \u00d7 n and B of any dimensions is given by A \u2297 B = \uf8ee \uf8ef \uf8ef \uf8ef \uf8ef \uf8f0 A 11 B A 12 B . . . A 1n B A 21 B A 22 B . . . A 2n [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":3974,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[489],"tags":[],"class_list":["post-3999","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-4-quantum-mechanics"],"jetpack_featured_media_url":"https:\/\/workhouse.sweetdishy.com\/wp-content\/uploads\/2024\/09\/quantum-computer-1.png","_links":{"self":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/3999","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/comments?post=3999"}],"version-history":[{"count":2,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/3999\/revisions"}],"predecessor-version":[{"id":4548,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/3999\/revisions\/4548"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media\/3974"}],"wp:attachment":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media?parent=3999"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/categories?post=3999"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/tags?post=3999"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}