{"id":4013,"date":"2024-09-19T21:41:24","date_gmt":"2024-09-19T21:41:24","guid":{"rendered":"https:\/\/workhouse.sweetdishy.com\/?p=4013"},"modified":"2024-09-24T10:49:55","modified_gmt":"2024-09-24T10:49:55","slug":"quantum-vs-classical-correlations","status":"publish","type":"post","link":"https:\/\/workhouse.sweetdishy.com\/index.php\/2024\/09\/19\/quantum-vs-classical-correlations\/","title":{"rendered":"Quantum vs. classical correlations"},"content":{"rendered":"\n<p>In what way are the quantum correlations in an entangled quantum state<\/p>\n\n\n\n<p>di\ufb00erent from correlations in a classical system? If a measurement of a quan-<\/p>\n\n\n\n<p>tum state yields a probabilistic outcome, could we not assume that the ob-<\/p>\n\n\n\n<p>servable measured has a de\ufb01nite value that was merely uncovered by the<\/p>\n\n\n\n<p>measurement? Then the probabilities encoded in a quantum state would be<\/p>\n\n\n\n<p>like classical probabilities, in that they indicate the lack of knowledge we have<\/p>\n\n\n\n<p>about the system. The correlations we just saw in the entangled pair would be<\/p>\n\n\n\n<p>just like those in classical systems. For instance, say I have a bag with pairs of<\/p>\n\n\n\n<p>socks of random colors, each in paired, unlabelled packets. Now suppose you<\/p>\n\n\n\n<p>pull out a packet at random, and give one of the pair each to Alice and Bob.<\/p>\n\n\n\n<p>If Alice \ufb01nds she got a red sock then immediately she can tell that Bob has<\/p>\n\n\n\n<p>a red sock too! Perfect correlation! As another example, if Alice found a left<\/p>\n\n\n\n<p>sock then she knows Bob has a right sock, without Bob looking at his sock:<\/p>\n\n\n\n<p>perfect anticorrelation.<\/p>\n\n\n\n<p>In what way is this (anti)correlation di\ufb00erent when we talk about a pair<\/p>\n\n\n\n<p>of quantum particles in a Bell state? Can it not be that the particles simply<\/p>\n\n\n\n<p>possess spin values that are the same (or opposite, depending on the state),<\/p>\n\n\n\n<p>and the measurements just discover these values? The question here is a subtle<\/p>\n\n\n\n<p>one: we will ask it again in a di\ufb00erent way. Can these correlations between en-<\/p>\n\n\n\n<p>tangled particles be explained by some hidden properties that are not evident<\/p>\n\n\n\n<p>in quantum theory, that are assigned speci\ufb01c values at the time of production?<\/p>\n\n\n\n<p>This feature has been thoroughly examined by many scholars. Most prac-<\/p>\n\n\n\n<p>tising physicists follow the practical school of thought, known as the Copen-<\/p>\n\n\n\n<p>hagen School, so-called after the city of famous physicist Niels Bohr, its<\/p>\n\n\n\n<p>main proponent. According to this school, Nature is nothing more than the<\/p>\n\n\n\n<p>experimental results, and there is no place for assumed hidden properties.<\/p>\n\n\n\n<p>In other words, the spin of the atom in the entangled pair doesn\u2019t have an<\/p>\n\n\n\n<p>objective existence until brought into being by a measurement<\/p>\n","protected":false},"excerpt":{"rendered":"<p>In what way are the quantum correlations in an entangled quantum state di\ufb00erent from correlations in a classical system? If a measurement of a quan- tum state yields a probabilistic outcome, could we not assume that the ob- servable measured has a de\ufb01nite value that was merely uncovered by the measurement? Then the probabilities encoded [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":4002,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[490],"tags":[],"class_list":["post-4013","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-5-interpreting-quantum-physics"],"jetpack_featured_media_url":"https:\/\/workhouse.sweetdishy.com\/wp-content\/uploads\/2024\/09\/atom-1.png","_links":{"self":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/4013","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/comments?post=4013"}],"version-history":[{"count":2,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/4013\/revisions"}],"predecessor-version":[{"id":4564,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/4013\/revisions\/4564"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media\/4002"}],"wp:attachment":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media?parent=4013"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/categories?post=4013"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/tags?post=4013"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}