{"id":4017,"date":"2024-09-19T21:43:41","date_gmt":"2024-09-19T21:43:41","guid":{"rendered":"https:\/\/workhouse.sweetdishy.com\/?p=4017"},"modified":"2024-09-24T10:48:27","modified_gmt":"2024-09-24T10:48:27","slug":"bells-inequalities-and-non-locality","status":"publish","type":"post","link":"https:\/\/workhouse.sweetdishy.com\/index.php\/2024\/09\/19\/bells-inequalities-and-non-locality\/","title":{"rendered":"Bell\u2019s inequalities and non-locality"},"content":{"rendered":"\n<p>Bell\u2019s original work, and many subsequent variants show how quantum<\/p>\n\n\n\n<p>correlations in an entangled state are essentially di\ufb00erent from classical ones.<\/p>\n\n\n\n<p>One of the inequalities of Bell applies to a physical system consisting of two<\/p>\n\n\n\n<p>subsystems, obeying the principle of local realism. He shows that the quantum<\/p>\n\n\n\n<p>statistics for such a system involving entangled subsystems will necessarily vi-<\/p>\n\n\n\n<p>olate this inequality, a statement generically known as \u201cBell\u2019s theorem\u201d [64].<\/p>\n\n\n\n<p>Subsequently many similar inequalities were discovered by various authors.<\/p>\n\n\n\n<p>(These are reviewed in [18].) We will discuss one of them (not Bell\u2019s original<\/p>\n\n\n\n<p>one!) to show how quantum correlations are intrinsically di\ufb00erent from classi-<\/p>\n\n\n\n<p>cal (local realist) ones. This follows original work by Clauser, Horne, Shimony<\/p>\n\n\n\n<p>and Holt [17](CHSH).<\/p>\n\n\n\n<p>We consider spin as an example but the derivation holds true for any<\/p>\n\n\n\n<p>dichotomic variable, i.e., one with measurements outcomes described by two<\/p>\n\n\n\n<p>values, \u00b11. Let\u2019s revisit the experiment of Figure 4.2.<\/p>\n\n\n\n<p>Consider a source emitting a very large number N of entangled spin-half<\/p>\n\n\n\n<p>pairs, and four arbitrary directions \u02c6a,<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>,<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b,<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>for SG machines chosen by Alice<\/p>\n\n\n\n<p>and Bob for measuring. Suppose that before measurement, the spin of the i<\/p>\n\n\n\n<p>th<\/p>\n\n\n\n<p>pair has hidden, \ufb01xed values r<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(a) and r<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>) for particle (1), s<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(b) and s<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>for particle (2) along the respective axes. The correlation between particles<\/p>\n\n\n\n<p>(1) and (2) can be measured by the average value of the product of spin<\/p>\n\n\n\n<p>measurements:<\/p>\n\n\n\n<p>C(a, b) =<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>N<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>r<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(a)s<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(b). (4.14)<\/p>\n\n\n\n<p>We will have similar expressions for C(a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>, b), C(a, b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>), and C(a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>, b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>), if the ex-<\/p>\n\n\n\n<p>periments used those pairs of axes for measurement. These expressions for the<\/p>\n\n\n\n<p>average are the same as for classical statistical averages.<\/p>\n\n\n\n<p>CHSH in their worked aimed to calculate the quantity<\/p>\n\n\n\n<p>C(a, b) + C(a, b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>) + C(a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>, b) \u2212 C(a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>, b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>). (4.15)<\/p>\n\n\n\n<p>We\u2019ll \ufb01rst see what the \u201cclassical\u201d value is, assuming hidden variable descrip-<\/p>\n\n\n\n<p>tion and then compare it with the predictions of quantum mechanics. First<\/p>\n\n\n\n<p>look at the possible combinations of spin values (in units of ~\/2) for the i<\/p>\n\n\n\n<p>th<\/p>\n\n\n\n<p>pair. We introduce the notation<\/p>\n\n\n\n<p>T<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>= r<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(a)[s<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(b) + s<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>)], T<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>= r<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>)[s<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(b) \u2212 s<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>)].<\/p>\n\n\n\n<p><\/p>\n\n\n\n<p>74 Introduction to Quantum Physics and Information Processing<\/p>\n\n\n\n<p>Observe that T<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>+ T<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>= \u00b12 always. For instance, when r<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(a) = +1, r<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>) =<\/p>\n\n\n\n<p>\u22121, s<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(b) = \u22121, s<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>(b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>) = +1, then T<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>= \u22122 and T<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>= 0. You can see similar<\/p>\n\n\n\n<p>results for all other combinations of values for these two spin measurements.<\/p>\n\n\n\n<p>To evaluate the sum 4.15, we just sum T<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>+ T<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>over all i and divide by N:<\/p>\n\n\n\n<p>|C(a, b) + C(a, b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>) + C(a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>, b) \u2212 C(a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>, b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>)| \u2264 2.. (4.16)<\/p>\n\n\n\n<p>This is the CHSH inequality.<\/p>\n\n\n\n<p>What does quantum mechanics predict for the sum (4.15)? Remember that<\/p>\n\n\n\n<p>the spins are not to have \ufb01xed values before measurement. The correlation<\/p>\n\n\n\n<p>between spins are now the quantum mechanical expectation values of spin<\/p>\n\n\n\n<p>operator products in the state of Equation 4.13:<\/p>\n\n\n\n<p>C(a, b) = h<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u03b2<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>. (4.17)<\/p>\n\n\n\n<p>Note that the operator<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>, spin along direction \u02c6a is just ~\u03c3 \u00b7\u02c6a (in units of ~\/2).<\/p>\n\n\n\n<p>You would have shown in Problem 3.12 (b) of Chapter 3, that the eigenvectors<\/p>\n\n\n\n<p>of<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>are given by<\/p>\n\n\n\n<p>|\u02c6a\u00b1i = e<\/p>\n\n\n\n<p>\u2212i<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>k\u00b7~\u03c3<\/p>\n\n\n\n<p>|Z\u00b1i.<\/p>\n\n\n\n<p>Here<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>k is a direction perpendicular to both \u02c6z and \u02c6a, i.e., parallel to \u02c6z \u00d7 \u02c6a.<\/p>\n\n\n\n<p>Example 4.4.1. Let\u2019s \ufb01nd the expectation value of<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>in the Bell state<\/p>\n\n\n\n<p>|\u03b2<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>i.<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>|\u03b2<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>i = ~\u03c3 \u00b7 \u02c6a(|01i \u2212 |10i)<\/p>\n\n\n\n<p>= (a<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>+ a<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>Y<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>+ a<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>Z<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>)(|01i \u2212 |10i)<\/p>\n\n\n\n<p>= a<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>(|11i \u2212 |00i) \u2212 ia<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>(|01i + |10i) + a<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>(|01i + |10i)<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>|\u03b2<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>i = \u2212a<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>|\u03b2<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>i \u2212 ia<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>(|10i + |01i) + a<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>(|10i + |11i)<\/p>\n\n\n\n<p>\u2212ia<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>(|00i + |11i) \u2212 a<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>|\u03b2<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>i + ia<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>(|01i \u2212 |10i)<\/p>\n\n\n\n<p>+a<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>(|11i + |00i) + ia<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>(|01i \u2212 |10i) \u2212 a<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>|\u03b2<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>i,<\/p>\n\n\n\n<p>h\u03b2<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>|<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>S<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>|\u03b2<\/p>\n\n\n\n<p>11<\/p>\n\n\n\n<p>i = \u2212a<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>x<\/p>\n\n\n\n<p>\u2212 a<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>y<\/p>\n\n\n\n<p>\u2212 a<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>z<\/p>\n\n\n\n<p>= \u2212\u02c6a \u00b7<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b.<\/p>\n\n\n\n<p>Then the left-hand side of Equation 4.16 is<\/p>\n\n\n\n<p>|\u02c6a \u00b7 (<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b +<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>) +<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>\u00b7 (<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b \u2212<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>)| \u2264 |\u02c6a||<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b +<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>| + |<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>||<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b \u2212<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>| (4.18)<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>\u221a<\/p>\n\n\n\n<p>2(<\/p>\n\n\n\n<p>p<\/p>\n\n\n\n<p>1 + cos \u03c6 +<\/p>\n\n\n\n<p>p<\/p>\n\n\n\n<p>1 \u2212 cos \u03c6)(4.19)<\/p>\n\n\n\n<p>where cos \u03c6 =<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b \u00b7<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>. (4.20)<\/p>\n\n\n\n<p>Now the minimum value this can take is obviously when cos \u03c6 = 0, and that<\/p>\n\n\n\n<p>value is 2<\/p>\n\n\n\n<p>\u221a<\/p>\n\n\n\n<p>2, greater than the CHSH bound. Thus there exist con\ufb01gurations<\/p>\n\n\n\n<p><\/p>\n\n\n\n<p>Properties of Qubits 75<\/p>\n\n\n\n<p>of detectors that can violate the CHSH inequality. See for instance Figure<\/p>\n\n\n\n<p>4.3. This leads us to conclude that quantum mechanics is NOT compatible<\/p>\n\n\n\n<p>with a local realistic description, that is, the assumption that the spins have<\/p>\n\n\n\n<p>values before they are measured must be wrong. The entangled state vector<\/p>\n\n\n\n<p>describes the pair as a single whole, with no room for describing the states<\/p>\n\n\n\n<p>of the individual constituents. They have no well-de\ufb01ned spin in such a state.<\/p>\n\n\n\n<p>There is therefore no way of setting about deriving the CHSH inequality for<\/p>\n\n\n\n<p>such a system: the spin values of particles (1) and (2) do not exist before they<\/p>\n\n\n\n<p>are measured.<\/p>\n\n\n\n<p>Example 4.4.2. Let\u2019s examine the directions for which the CHSH inequality is<\/p>\n\n\n\n<p>maximally violated. If cos \u03c6 = 0, then we have<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b \u22a5<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>. The RHS of inequality<\/p>\n\n\n\n<p>4.18 also shows that \u02c6a and<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b +<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>must be parallel or antiparallel, and so<\/p>\n\n\n\n<p>also<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>and<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b \u2212<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>must be parallel or antiparallel. One way of picking such<\/p>\n\n\n\n<p>directions is for Alice to choose \u02c6z and \u02c6x while Bob chooses the \u00b145<\/p>\n\n\n\n<p>\u25e6<\/p>\n\n\n\n<p>directions<\/p>\n\n\n\n<p>(<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>\u221a<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>\ue002<\/p>\n\n\n\n<p>\u02c6x + \u02c6z<\/p>\n\n\n\n<p>\ue003<\/p>\n\n\n\n<p>and<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>\u221a<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>\ue002<\/p>\n\n\n\n<p>\u02c6z \u2212 \u02c6x<\/p>\n\n\n\n<p>\ue003<\/p>\n\n\n\n<p>), as in Figure 4.3. Other sets of combinations are<\/p>\n\n\n\n<p>also possible that satisfy the above criterion (\ufb01nd them!). In the language<\/p>\n\n\n\n<p>of quantum mechanics, we must speak of the operators corresponding to the<\/p>\n\n\n\n<p>measurement axes of A and B: in other words, we talk of then measuring<\/p>\n\n\n\n<p>the operator \u03c3<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>or \u03c3<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>. Thus we speak of correlations between certain pairs of<\/p>\n\n\n\n<p>observables that violate the CHSH bound for classical correlations.<\/p>\n\n\n\n<p>FIGURE 4.3: Directions for SG detectors a, a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>, b and b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>and the corresponding<\/p>\n\n\n\n<p>observables measured by Alice and Bob, that maximally violate the CHSH<\/p>\n\n\n\n<p>inequality.<\/p>\n\n\n\n<p>The beauty of Bell\u2019s inequalities was that for the \ufb01rst time they provided a<\/p>\n\n\n\n<p>way to test quantum mechanics experimentally. The \ufb01rst experimental realiza-<\/p>\n\n\n\n<p>tion of this was performed by the group led by Alain Aspect in 1981 [2]. Since<\/p>\n\n\n\n<p>then, many experiments have been performed that con\ufb01rm the violation of<\/p>\n\n\n\n<p>the inequalities, and the corresponding interpretation of quantum mechanics<\/p>\n\n\n\n<p>as theory that intrinsically does not obey \u201clocal realism\u201d.<\/p>\n\n\n\n<p>However, some researchers have tried to come up with non-local theories<\/p>\n\n\n\n<p>that still are consistent with relativity, notably the GRW [37] theory of Ghi-<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" alt=\"\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9781482238129\/files\/bg65.png\" width=\"671\" height=\"509\"><\/p>\n\n\n\n<p>76 Introduction to Quantum Physics and Information Processing<\/p>\n\n\n\n<p>rardi, Rimini, and Weber, and Bohmian mechanics [22]. The debate still con-<\/p>\n\n\n\n<p>tinues as people come up with plausible non-local realistic theories to replace<\/p>\n\n\n\n<p>quantum mechanics!<\/p>\n\n\n\n<p>This section ought to have convinced you that quantum entanglement is<\/p>\n\n\n\n<p>something new and more than classical correlations: leading to its exploitation<\/p>\n\n\n\n<p>as a resource in information processing.<\/p>\n\n\n\n<p>Many of the original papers cited in this chapter are reprinted in an in-<\/p>\n\n\n\n<p>valuable volume by Wheeler and Zurek [72]. A wonderful discussion of many<\/p>\n\n\n\n<p>of the properties of quantum systems discussed here is given in the book by<\/p>\n\n\n\n<p>Aharonov and Rohrlich [1].<\/p>\n\n\n\n<p>Problems<\/p>\n\n\n\n<p>4.1. Find out what the action of each of the \u03c3<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>operators is on the Bloch sphere<\/p>\n\n\n\n<p>by checking their e\ufb00ects on the eigenvectors |Z\u00b1i, |X\u00b1i and |Y \u00b1i.<\/p>\n\n\n\n<p>4.2. Prove that the Bell states are mutually orthogonal and that they form<\/p>\n\n\n\n<p>a basis for H<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>. You must be able to express an arbitrary 2-qubit state<\/p>\n\n\n\n<p>|\u03c8i = a|00i + b|01i + c|10i + d|11i as a linear superposition of the Bell<\/p>\n\n\n\n<p>states. Find the coe\ufb03cients in this superposition in terms of a, b, c, and d.<\/p>\n\n\n\n<p>4.3. Entanglement and basis change: suppose |s<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>i and |s<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i, linear combinations<\/p>\n\n\n\n<p>of the basis states |0i and |1i form an orthonormal basis for a spin Hilbert<\/p>\n\n\n\n<p>space. Show that the two-spin entangled \u201csinglet\u201d state<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>\u221a<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>(|s<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>i \u2297 |s<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i \u2212 |s<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i \u2297 |s<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>i)<\/p>\n\n\n\n<p>is equivalent to<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>\u221a<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>(|01i \u2212 |10i).<\/p>\n\n\n\n<p>Check that this preservation of the form of entanglement does not hold for<\/p>\n\n\n\n<p>the other three Bell states in the transformed basis.<\/p>\n\n\n\n<p>4.4. We found the directions \u02c6a,<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>a<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>,<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b, and<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>b<\/p>\n\n\n\n<p>0<\/p>\n\n\n\n<p>of Stern\u2013Gerlach machines for<\/p>\n\n\n\n<p>which the CHSH inequality is maximally violated for spin half particles.<\/p>\n\n\n\n<p>Translate this experiment to photon polarization measurements and \ufb01nd<\/p>\n\n\n\n<p>the corresponding directions for the axes of polarizers used by Alice and<\/p>\n\n\n\n<p>Bob that would maximally violate the CHSH inequality.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Bell\u2019s original work, and many subsequent variants show how quantum correlations in an entangled state are essentially di\ufb00erent from classical ones. One of the inequalities of Bell applies to a physical system consisting of two subsystems, obeying the principle of local realism. He shows that the quantum statistics for such a system involving entangled subsystems [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":4002,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[490],"tags":[],"class_list":["post-4017","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-5-interpreting-quantum-physics"],"jetpack_featured_media_url":"https:\/\/workhouse.sweetdishy.com\/wp-content\/uploads\/2024\/09\/atom-1.png","_links":{"self":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/4017","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/comments?post=4017"}],"version-history":[{"count":2,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/4017\/revisions"}],"predecessor-version":[{"id":4563,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/4017\/revisions\/4563"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media\/4002"}],"wp:attachment":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media?parent=4017"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/categories?post=4017"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/tags?post=4017"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}