{"id":4035,"date":"2024-09-19T21:57:41","date_gmt":"2024-09-19T21:57:41","guid":{"rendered":"https:\/\/workhouse.sweetdishy.com\/?p=4035"},"modified":"2024-09-24T11:14:46","modified_gmt":"2024-09-24T11:14:46","slug":"composite-systems-2","status":"publish","type":"post","link":"https:\/\/workhouse.sweetdishy.com\/index.php\/2024\/09\/19\/composite-systems-2\/","title":{"rendered":"Composite Systems"},"content":{"rendered":"\n<p>There is another sense in which density operators are a useful way to<\/p>\n\n\n\n<p>describe nature. In general, it is impossible to isolate the system of interest<\/p>\n\n\n\n<p>from some parts of its environment. We then have to regard our system as a<\/p>\n\n\n\n<p>subsystem of a larger system: \u201csystem + environment\u201d. If the large system in a<\/p>\n\n\n\n<p>pure quantum state consists of subsystems, then the state of any subsystem is<\/p>\n\n\n\n<p>essentially described by a density operator. The way to get there is to perform<\/p>\n\n\n\n<p>a reduction of the density matrix of the larger system, by a procedure called<\/p>\n\n\n\n<p>the partial trace over all subsystems except the one of interest.<\/p>\n\n\n\n<p>5.3.1 Reduced density operator<\/p>\n\n\n\n<p>Consider a composite of two systems A and B, described by a pure state<\/p>\n\n\n\n<p>density operator \u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>FIGURE 5.5: Illustrating a bipartite composite system.<\/p>\n\n\n\n<p>For the purposes of this book, we will only concentrate on systems consist-<\/p>\n\n\n\n<p><\/p>\n\n\n\n<p>Mixed States, Open Systems, and the Density Operator 93<\/p>\n\n\n\n<p>ing of two subsystems, the so-called bipartite systems (Figure 5.5). We can<\/p>\n\n\n\n<p>perform a partial trace over the system B alone to obtain the state of system<\/p>\n\n\n\n<p>A. If the set {|k<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i} forms a basis for system B then<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>= Tr<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>k<\/p>\n\n\n\n<p>hk<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>|\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>|k<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i. (5.34)<\/p>\n\n\n\n<p>Trace operation is linear, and if we demand that partial trace is also linear in<\/p>\n\n\n\n<p>its inputs, we can compute partial traces in practice.<\/p>\n\n\n\n<p>De\ufb01nition 5.4. If subsystems A and B are given by Hilbert spaces spanned<\/p>\n\n\n\n<p>by the bases {|i<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i} and {|j<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i} respectively, we de\ufb01ne the partial trace of \u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>with respect to subsystem A as<\/p>\n\n\n\n<p>Tr<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>hi<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>|\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>|i<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i (5.35)<\/p>\n\n\n\n<p>which will be an operator on the Hilbert space of subsystem B alone.<\/p>\n\n\n\n<p>Example 5.3.1. Consider a simple example where the system state can be<\/p>\n\n\n\n<p>written in separable form:<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>= \u03c3<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>\u2297 \u03c3<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>Then quite trivially,<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>= Tr<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>(\u03c3<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>\u2297 \u03c3<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>) = \u03c3<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>Tr<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>\u03c3<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>= \u03c3<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>Example 5.3.2. A less trivial case where the two subsystems are entangled,<\/p>\n\n\n\n<p>so that the state of the system is a Bell state:<\/p>\n\n\n\n<p>|\u03c8<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>i =<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>\u221a<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>\ue000<\/p>\n\n\n\n<p>|0<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i|0<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i + |1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i|1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\ue001<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>=\u21d2 \u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>= |\u03c8<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>ih\u03c8<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>|<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>(|00ih00| + |00ih11| + |11ih00| + |11ih11|) .<\/p>\n\n\n\n<p>To obtain \u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>by a partial trace over B, we sandwich each term between the<\/p>\n\n\n\n<p>basis states of B and add up:<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>= Tr<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>= h0<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>|\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>|0<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i + h1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>|\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>|1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p><\/p>\n\n\n\n<p>94 Introduction to Quantum Physics and Information Processing<\/p>\n\n\n\n<p>We illustrate the calculation of this by \ufb01rst evaluating the contribution by the<\/p>\n\n\n\n<p>\ufb01rst term in \u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>:<\/p>\n\n\n\n<p>h0<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>|(|00ih00|) |0<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i + h1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>|(|00ih00|) |1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>= |0ih0<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>|0ih0|h0|0<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i + |0ih1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>|0ih0|h0|1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>= |0ih0| + 0.<\/p>\n\n\n\n<p>Evaluating the other terms similarly, we \ufb01nd that<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>(|0ih0| + |1ih1|) =<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>Thus the subsystem A is in a maximally mixed state! Similarly,<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>= Tr<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>This result is a hallmark of entanglement: though the composite system is<\/p>\n\n\n\n<p>in a well-de\ufb01ned state, i.e., its density operator contains maximal informa-<\/p>\n\n\n\n<p>tion about all measurement outcomes in the state, we can say nothing about<\/p>\n\n\n\n<p>measurement outcomes on either of the component subsystems: they are in<\/p>\n\n\n\n<p>maximally mixed states.<\/p>\n\n\n\n<p>Exercise 5.9. Calculate the density matrices for both subsystems for the other<\/p>\n\n\n\n<p>three Bell states.<\/p>\n\n\n\n<p>Exercise 5.10. Consider a 2-qubit system AB with the density matrix \u03c1 =<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>|\u03b2<\/p>\n\n\n\n<p>00<\/p>\n\n\n\n<p>ih\u03b2<\/p>\n\n\n\n<p>00<\/p>\n\n\n\n<p>| +<\/p>\n\n\n\n<p>1<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>|10ih10|. Compute the reduced density matrices \u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>and<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>The fact that the reduced density matrices for entangled systems represent<\/p>\n\n\n\n<p>mixed states is generic, and can be used to characterize entanglement. As we<\/p>\n\n\n\n<p>have already seen, the reduced density matrices for separable systems will<\/p>\n\n\n\n<p>always be pure.<\/p>\n\n\n\n<p>Box 5.1: POVM from Projective Measurements on a Composite System<\/p>\n\n\n\n<p>POVM measurements on quantum systems can be realized as projective<\/p>\n\n\n\n<p>measurements on an extended \u201csystem+ancilla\u201d Hilbert space. Let\u2019s consider<\/p>\n\n\n\n<p>a system A that is not interacting with the independent ancilla B. The com-<\/p>\n\n\n\n<p>bined AB system is in a product state that can be represented by the density<\/p>\n\n\n\n<p>operator<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>= \u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>\u2297 \u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>A projective measurement on this state is the action of projection operators<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" alt=\"\" src=\"https:\/\/learning.oreilly.com\/api\/v2\/epubs\/urn:orm:book:9781482238129\/files\/bg78.png\" width=\"685\" height=\"687\"><\/p>\n\n\n\n<p>Mixed States, Open Systems, and the Density Operator 95<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>on this state. The probability of outcome m is then<\/p>\n\n\n\n<p>P(m) = Tr<\/p>\n\n\n\n<p>h<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>(\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>\u2297 \u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>= Tr<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>h<\/p>\n\n\n\n<p>Tr<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>\ue010<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>\u2297 \u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>\ue011i<\/p>\n\n\n\n<p>= Tr<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>(<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>E<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>) (5.36)<\/p>\n\n\n\n<p>where the<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>E<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>s are operators on the system A. We can identify the matrix<\/p>\n\n\n\n<p>elements of these operators by expressing the above equation in components:<\/p>\n\n\n\n<p>using orthonormal bases {|ii} for the system A and {|\u00b5i} for the ancilla B,<\/p>\n\n\n\n<p>Tr<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>\ue010<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>\u2297 \u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>\ue011<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>ij\u00b5\u03bd<\/p>\n\n\n\n<p>(<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>j\u03bdi\u00b5<\/p>\n\n\n\n<p>(\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>ij<\/p>\n\n\n\n<p>(\u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>\u00b5\u03bd<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>ij<\/p>\n\n\n\n<p>(E<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>ji<\/p>\n\n\n\n<p>(\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>ij<\/p>\n\n\n\n<p>=\u21d2 (E<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>ji<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>\u00b5\u03bd<\/p>\n\n\n\n<p>(<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>j\u03bdi\u00b5<\/p>\n\n\n\n<p>(\u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>)<\/p>\n\n\n\n<p>\u00b5\u03bd<\/p>\n\n\n\n<p>.<\/p>\n\n\n\n<p>It is easy to see that the<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>E<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>s de\ufb01ned this way are complete. Suppose \u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>is<\/p>\n\n\n\n<p>diagonal in the basis {|\u00b5i}:<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>\u00b5<\/p>\n\n\n\n<p>p<\/p>\n\n\n\n<p>\u00b5<\/p>\n\n\n\n<p>|\u00b5ih\u00b5|,<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>E<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>\u00b5<\/p>\n\n\n\n<p>p<\/p>\n\n\n\n<p>\u00b5<\/p>\n\n\n\n<p>h\u00b5|<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>\u02c6<\/p>\n\n\n\n<p>m<\/p>\n\n\n\n<p>|\u00b5i = .<\/p>\n\n\n\n<p>5.3.2 Schmidt decomposition<\/p>\n\n\n\n<p>Another useful way of dealing with composite systems, the Schmidt de-<\/p>\n\n\n\n<p>composition is about expressing the state of a bipartite system in terms of<\/p>\n\n\n\n<p>orthonormal states of the two subsystems.<\/p>\n\n\n\n<p>Theorem 5.2. If {|u<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>i} and {|v<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>j<\/p>\n\n\n\n<p>i} are orthonormal sets of vectors in the<\/p>\n\n\n\n<p>Hilbert spaces of subsystems A and B, respectively, the state of the combined<\/p>\n\n\n\n<p>system can be expressed as<\/p>\n\n\n\n<p>|\u03c8<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>i =<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u03bb<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>|u<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>i|v<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>i. (5.37)<\/p>\n\n\n\n<p>The constants \u03bb<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>are called Schmidt coe\ufb03cients, and are non-negative real<\/p>\n\n\n\n<p>numbers satisfying<\/p>\n\n\n\n<p>P<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u03bb<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>= 1. The number of terms in the expansion is known<\/p>\n\n\n\n<p><\/p>\n\n\n\n<p>96 Introduction to Quantum Physics and Information Processing<\/p>\n\n\n\n<p>as the Schmidt number. While such an expansion may not in general be<\/p>\n\n\n\n<p>unique, the Schmidt number is unique for a given state.<\/p>\n\n\n\n<p>Proof. The Schmidt decomposition theorem (5.37) can be proved by simple<\/p>\n\n\n\n<p>results in linear algebra.<\/p>\n\n\n\n<p>Consider a general pure state in the computational basis {|i<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i|j<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i}:<\/p>\n\n\n\n<p>|\u03c8i =<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>ij<\/p>\n\n\n\n<p>C<\/p>\n\n\n\n<p>ij<\/p>\n\n\n\n<p>|ii|ji.<\/p>\n\n\n\n<p>Now the matrix C of complex numbers is a square matrix, and therefore (from<\/p>\n\n\n\n<p>results in linear algebra) has a singular value decomposition (SVD) of the form<\/p>\n\n\n\n<p>C = UDV where D is a diagonal matrix and U and V are unitaries. So we<\/p>\n\n\n\n<p>can write<\/p>\n\n\n\n<p>|\u03c8i =<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>ij<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>k<\/p>\n\n\n\n<p>U<\/p>\n\n\n\n<p>ik<\/p>\n\n\n\n<p>D<\/p>\n\n\n\n<p>kk<\/p>\n\n\n\n<p>V<\/p>\n\n\n\n<p>kj<\/p>\n\n\n\n<p>|ii|ji.<\/p>\n\n\n\n<p>By de\ufb01ning D<\/p>\n\n\n\n<p>kk<\/p>\n\n\n\n<p>= \u03bb<\/p>\n\n\n\n<p>k<\/p>\n\n\n\n<p>,<\/p>\n\n\n\n<p>P<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>U<\/p>\n\n\n\n<p>ik<\/p>\n\n\n\n<p>|ii = |u<\/p>\n\n\n\n<p>k<\/p>\n\n\n\n<p>i,<\/p>\n\n\n\n<p>P<\/p>\n\n\n\n<p>j<\/p>\n\n\n\n<p>V<\/p>\n\n\n\n<p>kj<\/p>\n\n\n\n<p>|ji = |v<\/p>\n\n\n\n<p>k<\/p>\n\n\n\n<p>i we get the form of<\/p>\n\n\n\n<p>Equation 5.37 for |\u03c8i.<\/p>\n\n\n\n<p>In terms of density matrices,<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>AB<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u03bb<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>|u<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>ihu<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>| \u2297 |v<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>ihv<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>|. (5.38)<\/p>\n\n\n\n<p>If we perform partial traces on this, we will get<\/p>\n\n\n\n<p>\u03c1<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u03bb<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>|u<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>ihu<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>|, \u03c1<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>=<\/p>\n\n\n\n<p>X<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>\u03bb<\/p>\n\n\n\n<p>2<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>|v<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>ihv<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>|, (5.39)<\/p>\n\n\n\n<p>There are some important take-home points to note here:<\/p>\n\n\n\n<p>\u2022 Both the reduced density matrices have the same eigenvalues.<\/p>\n\n\n\n<p>\u2022 \u03c1 could have zero eigenvalues and those terms are not present in the<\/p>\n\n\n\n<p>expansion above. So the sets {|u<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>i<\/p>\n\n\n\n<p>i} and {|v<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>j<\/p>\n\n\n\n<p>i} are not bases for H<\/p>\n\n\n\n<p>A<\/p>\n\n\n\n<p>and H<\/p>\n\n\n\n<p>B<\/p>\n\n\n\n<p>, but can be extended to bases by including eigenvectors for the<\/p>\n\n\n\n<p>zero eigenvalues.<\/p>\n\n\n\n<p>If the composite system is in a product state, then there is obviously only<\/p>\n\n\n\n<p>one term in the Schmidt decomposition. Thus the Schmidt number for product<\/p>\n\n\n\n<p>states is always 1. Therefore an entangled state has Schmidt number &gt; 1. This<\/p>\n\n\n\n<p>is one of the \ufb01rst ways of quantifying entanglement.<\/p>\n\n\n\n<p>Example 5.3.3. Let\u2019s \ufb01nd the Schmidt form of some simple states:<\/p>\n","protected":false},"excerpt":{"rendered":"<p>There is another sense in which density operators are a useful way to describe nature. In general, it is impossible to isolate the system of interest from some parts of its environment. We then have to regard our system as a subsystem of a larger system: \u201csystem + environment\u201d. If the large system in a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":4020,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[491],"tags":[],"class_list":["post-4035","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-5-grand-unification"],"jetpack_featured_media_url":"https:\/\/workhouse.sweetdishy.com\/wp-content\/uploads\/2024\/09\/quantum-1.png","_links":{"self":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/4035","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/comments?post=4035"}],"version-history":[{"count":2,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/4035\/revisions"}],"predecessor-version":[{"id":4570,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/posts\/4035\/revisions\/4570"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media\/4020"}],"wp:attachment":[{"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/media?parent=4035"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/categories?post=4035"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/workhouse.sweetdishy.com\/index.php\/wp-json\/wp\/v2\/tags?post=4035"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}